{"id":17687,"date":"2024-03-12T04:16:50","date_gmt":"2024-03-12T04:16:50","guid":{"rendered":"https:\/\/soicau5081.minhngocxoso.com\/?p=17687"},"modified":"2024-03-12T04:16:50","modified_gmt":"2024-03-12T04:16:50","slug":"ky-thuat-danh-thang-lo-xien-ban-can-biet-ngay","status":"publish","type":"post","link":"https:\/\/chotsochinhxac100.com\/ky-thuat-danh-thang-lo-xien-ban-can-biet-ngay\/","title":{"rendered":"k\u1ef9 thu\u1eadt \u0111\u00e1nh th\u1eafng l\u00f4 xi\u00ean b\u1ea1n c\u1ea7n bi\u1ebft ngay"},"content":{"rendered":"
<\/p>\n\n\n
\u0110\u1ed1i v\u1edbi nh\u1eefng cao th\u1ee7 ch\u01a1i l\u00f4 \u0111\u1ec1 x\u1ed5 s\u1ed1 online chuy\u00ean nghi\u1ec7p th\u00ec c\u00e1ch xem l\u00f4 xi\u00ean chu\u1ea9n x\u00e1c kh\u00f4ng c\u00f2n xa l\u1ea1 g\u00ec n\u1eefa. Nh\u01b0ng \u0111\u1ec3 hi\u1ec3u r\u00f5 v\u00e0 cach danh lo xien ra sao th\u00ec kh\u00f4ng ph\u1ea3i ai c\u0169ng l\u00e0m \u0111\u01b0\u1ee3c. \u1ede b\u00e0i vi\u1ebft n\u00e0y s\u1ebd chia s\u1ebb \u0111\u1ebfn c\u00e1c b\u1ea1n c\u00e1ch \u0111\u00e1nh l\u00f4 xi\u00ean quay sao cho hi\u1ec7u qu\u1ea3 nh\u1ea5t.<\/p>\n\n\n\n
Xi\u00ean quay c\u00f3 nhi\u1ec1u h\u00ecnh th\u1ee9c \u0111\u00e1nh nh\u01b0 xi\u00ean quay 2,3 v\u00e0 4. V\u1eady chi ti\u1ebft t\u1eebng c\u00e1ch \u0111\u00e1nh l\u00e0 nh\u01b0 th\u1ebf n\u00e0o? C\u00e1ch t\u00ednh th\u1eafng thua ra sao? H\u00e3y c\u00f9ng theo d\u00f5i d\u01b0\u1edbi \u0111\u00e2y.<\/p>\n\n\n\n
L\u00f4 xi\u00ean quay 2 l\u00e0 t\u1ed5 h\u1ee3p c\u00e1c c\u1eb7p xi\u00ean 2 c\u00f3 trong b\u1ed9 s\u1ed1 m\u00e0 anh em mu\u1ed1n \u0111\u00e1nh. \u0110i\u1ec1u ki\u1ec7n \u0111\u1ec3 th\u1eafng l\u00e0 anh em ph\u1ea3i tr\u00fang c\u1ea3 2 con trong b\u1ed9 xi\u00ean th\u00ec m\u1edbi \u0111\u01b0\u1ee3c nh\u1eadn th\u01b0\u1edfng.<\/p>\n\n\n\n
V\u00ed d\u1ee5:<\/p>\n\n\n\n
\u0110\u00e1nh quay 2 v\u1edbi b\u1ed9 s\u1ed1 01, 02, 03 s\u1ebd bao g\u1ed3m \u0111\u00e1nh 3 c\u1eb7p xi\u00ean 2 l\u00e0 01 \u2013 02, 01 \u2013 03, 02- 03.<\/p>\n\n\n\n
Ti\u1ec1n v\u1ed1n: Anh em ch\u01a1i 10.000 \u0111\u1ed3ng th\u00ec ph\u1ea3i tr\u1ea3 cho c\u1ea3 3 con xi\u00ean 2 t\u1ed5ng c\u1ed9ng l\u00e0 30.000 \u0111\u1ed3ng.<\/p>\n\n\n\n
Tr\u00fang th\u01b0\u1edfng: Tr\u00fang 1 c\u1eb7p xi\u00ean 2 th\u00ec \u0103n, 2 c\u1eb7p xi\u00ean 2 c\u00f9ng v\u1ec1 th\u00ec nh\u00e2n \u0111\u00f4i ti\u1ec1n th\u01b0\u1edfng.<\/p>\n\n\n\n
L\u00f4 xi\u00ean quay 3 l\u00e0 t\u1ed5 h\u1ee3p c\u00e1c c\u1eb7p xi\u00ean 3 c\u00f3 trong b\u1ed9 s\u1ed1 m\u00e0 anh em mu\u1ed1n \u0111\u00e1nh. N\u1ebfu anh em tr\u00fang c\u1ea3 3 con th\u00ec \u0111\u01b0\u1ee3c t\u00ednh l\u00e0 \u0103n xi\u00ean 3, tr\u01b0\u1ee3t 1 con tr\u00fang 2 con th\u00ec \u0111\u01b0\u1ee3c t\u00ednh l\u00e0 \u0103n xi\u00ean 2, tr\u01b0\u1ee3t 2 con th\u00ec anh em thua.<\/p>\n\n\n\n
\u0110\u00e1nh xi\u00ean quay 3 v\u1edbi b\u1ed9 s\u1ed1 01, 02, 03, 04 s\u1ebd bao g\u1ed3m \u0111\u00e1nh 4 c\u1eb7p l\u00f4 xi\u00ean 3 l\u00e0 01 \u2013 02 \u2013 03, 01 \u2013 02 \u2013 04, 02 \u2013 03 \u2013 04, 01 \u2013 03 \u2013 04.<\/p>\n\n\n\n
Ti\u1ec1n v\u1ed1n: Anh em ch\u01a1i 10.000\u0111 th\u00ec ph\u1ea3i tr\u1ea3 cho c\u1ea3 4 con xi\u00ean 3 t\u1ed5ng c\u1ed9ng l\u00e0 40.000\u0111.<\/p>\n\n\n\n
Tr\u00fang th\u01b0\u1edfng: Tr\u00fang 1 c\u1eb7p xi\u00ean 3 th\u00ec \u0103n, 2 c\u1eb7p xi\u00ean 3 th\u00ec nh\u00e2n \u0111\u00f4i ti\u1ec1n th\u01b0\u1edfng,\u2026 V\u00ed d\u1ee5 trong b\u1ed9 xi\u00ean 3: 01 \u2013 02 \u2013 03 m\u00e0 ch\u1ec9 tr\u00fang 01 \u2013 02 th\u00ec anh em \u0111\u01b0\u1ee3c t\u00ednh l\u00e0 \u0103n m\u1ed9t con xi\u00ean 2.<\/p>\n\n\n\n
X\u00e1c su\u1ea5t tr\u00fang xi\u00ean quay 3 \u0111\u01b0\u1ee3c t\u00ednh theo c\u00f4ng th\u1ee9c nh\u01b0 sau: 21,5% x 21,5% x 21,5% = 0.0134 = 1.34%.<\/p>\n\n\n\n
Bao g\u1ed3m: 1 c\u1eb7p xi\u00ean 3 v\u00e0 2 c\u1eb7p xi\u00ean 2.<\/p>\n\n\n\n
Ngo\u00e0i c\u00e1ch ch\u01a1i l\u00f4 xi\u00ean hi\u1ec7u qu\u1ea3, th\u00ec c\u00e1ch \u0111\u00e1nh \u0111\u1ec1 \u0111\u1ea7u \u0111u\u00f4i c\u0169ng l\u00e0 m\u1ed9t trong nh\u1eefng c\u00e1ch \u0111\u00e1nh \u0111\u01b0\u1ee3c d\u00e2n ch\u01a1i l\u00f4 \u0111\u1ec1 c\u1ef1c k\u1ef3 \u01b0a th\u00edch.<\/p>\n\n\n\n
C\u00e1ch ch\u01a1i l\u00f4 xi\u00ean quay 4 l\u00e0 t\u1ed5 h\u1ee3p c\u00e1c c\u1eb7p xi\u00ean 4 c\u00f3 trong b\u1ed9 s\u1ed1 m\u00e0 anh em mu\u1ed1n \u0111\u00e1nh. N\u1ebfu tr\u00fang c\u1ea3 4 con th\u00ec \u0111\u01b0\u1ee3c t\u00ednh l\u00e0 \u0103n xi\u00ean 4, tr\u01b0\u1ee3t 2 con tr\u00fang 2 con th\u00ec \u0111\u01b0\u1ee3c t\u00ednh l\u00e0 \u0103n xi\u00ean 2, tr\u01b0\u1ee3t 1 con tr\u00fang 3 con th\u00ec \u0111\u01b0\u1ee3c t\u00ednh l\u00e0 \u0103n xi\u00ean 3, tr\u01b0\u1ee3t 3 con th\u00ec anh em thua. V\u00ed d\u1ee5 nh\u01b0:<\/p>\n\n\n\n
\u0110\u00e1nh xi\u00ean quay 4 v\u1edbi b\u1ed9 s\u1ed1 01,02,03,04,05 s\u1ebd bao g\u1ed3m \u0111\u00e1nh 5 c\u1eb7p l\u00f4 xi\u00ean 4 l\u00e0 01-02-03-04, 01-02-03-05.<\/p>\n\n\n\n
Ti\u1ec1n v\u1ed1n: Anh em ch\u01a1i 10.000 \u0111\u1ed3ng th\u00ec ph\u1ea3i tr\u1ea3 cho c\u1ea3 5 con xi\u00ean 5 t\u1ed5ng c\u1ed9ng l\u00e0 50.000 \u0111\u1ed3ng<\/p>\n\n\n\n
Tr\u00fang th\u01b0\u1edfng: tr\u00fang 1 c\u1eb7p l\u00e0 \u0103n, 2 c\u1eb7p th\u00ec nh\u00e2n \u0111\u00f4i ti\u1ec1n th\u01b0\u1edfng<\/p>\n\n\n\n
X\u00e1c su\u1ea5t tr\u00fang \u0111\u01b0\u1ee3c quay 4 \u0111\u01b0\u1ee3c t\u00ednh theo c\u00f4ng th\u1ee9c nh\u01b0: 21.5% x 21,5% x 21,5% x 21,5% = 0.00214.<\/p>\n\n\n\n
Bao g\u1ed3m 1 c\u1eb7p xi\u00ean 4, 4 c\u1eb7p xi\u00ean 3 v\u00e0 6 c\u1eb7p xi\u00ean 2.<\/p>\n\n\n\n
Kinh nghi\u1ec7m c\u00e1ch b\u1eaft l\u00f4 xi\u00ean chu\u1ea9n tr\u00fang l\u00f4 xi\u00ean 2, l\u00f4 xi\u00ean 3<\/p>\n\n\n
<\/p>\n\n\n
C\u00e1ch t\u00ednh xi\u00ean l\u00f4 l\u00e0 c\u00f9ng l\u00fac ch\u1ecdn \u0111\u00e1nh nhi\u1ec1u s\u1ed1 kh\u00e1c nhau, khi t\u1ea5t c\u1ea3 c\u00f9ng ra s\u1ed1 th\u00ec s\u1ebd \u0103n, nh\u01b0ng hi\u1ec7n nay c\u00f3 kh\u00f4ng \u00edt ng\u01b0\u1eddi \u0111\u00e1nh l\u00f4 xi\u00ean ch\u1ec9 nh\u0103m nh\u0103m quan t\u00e2m \u0111\u1ebfn khi tr\u00fang ph\u1ea7n th\u01b0\u1edfng nh\u01b0 th\u1ebf n\u00e0o c\u00f2n kh\u00f4ng bi\u1ebft \u0111\u1ebfn \u0111\u1ed9 kh\u00f3 khi ch\u01a1i l\u00f4 xi\u00ean. B\u1edfi \u0111\u00e1nh l\u00f4 xi\u00ean chi ph\u00ed th\u1ea5p thu h\u00fat nhi\u1ec1u ng\u01b0\u1eddi ch\u01a1i.<\/p>\n\n\n\n
Nh\u01b0 c\u00e1c b\u1ea1n \u0111\u00e3 bi\u1ebft, c\u00f3 27 gi\u1ea3i k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1, nh\u01b0ng th\u1ed1ng k\u00ea ch\u00fang t\u00f4i t\u1ed5ng k\u1ebft \u0111\u01b0\u1ee3c ch\u1ec9 c\u00f3 21,5 s\u1ed1 kh\u00e1c nhau. Do \u0111\u00f3, x\u00e1c su\u1ea5t \u0111\u1ec3 \u0111\u00e1nh con b\u1ea1ch th\u1ee7 m\u1ed9t s\u1ed1 duy nh\u1ea5t hay c\u00f2n g\u1ecdi xi\u00ean 1 l\u00e0 21,5%. V\u1eady b\u1ea1n th\u1ea5y d\u1ec5 hay kh\u00f3? B\u00ecnh qu\u00e2n 5 s\u1ed1 may ra c\u00f3 1 s\u1ed1 tr\u00fang m\u00e0 x\u00e1c su\u1ea5t \u0103n \u0111\u01b0\u1ee3c l\u00f4 xi\u00ean 1 nh\u1ecf h\u01a1n ch\u01a1i x\u00f3c \u0111\u0129a t\u1edbi 2,5 l\u1ea7n v\u00ec x\u00f3c \u0111\u0129a c\u00f3 x\u00e1c su\u1ea5t ch\u01a1i th\u1eafng \u0111\u1ebfn 50%.<\/p>\n\n\n\n
C\u00f2n v\u1edbi xi\u00ean 2, x\u00e1c su\u1ea5t \u0111\u00e1nh tr\u00fang l\u00e0 21,5% x 21,5% = 0,0462 -> x\u00e1c su\u1ea5t \u0111\u00e1nh tr\u00fang ch\u1ec9 c\u00f3 4,6%.<\/p>\n\n\n\n
L\u00f4 xi\u00ean 3 x\u00e1c xu\u1ea5t tr\u00fang b\u1eb1ng 21,5% x 21,5% x 21,5% =00994 -> x\u00e1c su\u1ea5t \u0111\u00e1nh tr\u00fang c\u00f3 0,994%.<\/p>\n\n\n\n
Khi \u0111\u00e1nh l\u00f4 xi\u00ean, m\u1ecdi ng\u01b0\u1eddi n\u00ean bi\u1ebft nh\u1eefng con s\u1ed1 n\u00e0o hay r\u1ee7 nhau c\u00f9ng ra. \u0110\u1ec3 d\u1ef1a v\u00e0o nh\u1eefng con s\u1ed1 \u0111\u00f3, ng\u01b0\u1eddi \u0111\u00e1nh l\u00f4 xi\u00ean r\u1ea5t d\u1ec5 tr\u00fang b\u1edfi th\u1ef1c t\u1ebf cho th\u1ea5y m\u1ed9t s\u1ed1 th\u01b0\u1eddng hay ra c\u00f9ng v\u1edbi m\u1ed9t v\u00e0i con s\u1ed1 kh\u00e1c.<\/p>\n\n\n\n
C\u00e1c con l\u00f4 hay ra h\u1eb1ng ng\u00e0y nh\u1ea5t: 75-79-92-373-565<\/p>\n\n\n\n
C\u00e1c c\u1eb7p l\u00f4 hay \u0111i k\u00e8m nhau: 373-010; 25 ho\u1eb7c 52-22; 76-47; 11-44; 33-66.<\/p>\n\n\n\n
L\u00f4 ra c\u1ea3 c\u1eb7p 060 th\u00ec h\u00f4m sau s\u1ebd r\u01a1i l\u1ea1i 1 s\u1ed1<\/p>\n\n\n\n
H\u00f4m tr\u01b0\u1edbc c\u00f3 l\u00f4 51 th\u00ec h\u00f4m sau c\u00f3 l\u00f4 15 ho\u1eb7c c\u00f3 c\u1ea3 c\u1eb7p 15 v\u00e0 51<\/p>\n\n\n\n
L\u00f4 ra c\u1ea3 c\u1eb7p 05 v\u00e0 50 ho\u1eb7c \u0111\u1ed5 1 con th\u00ec h\u00f4m sau s\u1ebd \u0111\u1ed5 l\u1ea1i 1 con.<\/p>\n\n\n\n
L\u00f4 ra c\u1ea3 c\u1eb7p 02 v\u00e0 20 ho\u1eb7c h\u00f4m tr\u01b0\u1edbc \u0111\u1ed5 1 con th\u00ec h\u00f4m sau s\u1ebd \u0111\u1ed5 l\u1ea1i 1 con.<\/p>\n\n\n\n
C\u00f3 l\u00f4 \u0111\u1ea7u 7 hay l\u00f4 \u0111\u00edt 3 m\u00e0 c\u00e2m th\u00ec h\u00f4m sau s\u1ebd v\u1ec1 con 73.<\/p>\n\n\n\n
Tr\u00ean \u0111\u00e2y l\u00e0 nh\u1eefng kinh nghi\u1ec7m c\u00e1ch xem l\u00f4 xi\u00ean hi\u1ec7u qu\u1ea3, t\u1eeb \u0111\u00f3 ng\u01b0\u1eddi ch\u01a1i s\u1ebd \u0111\u01b0a ra cho m\u00ecnh m\u1ed9t ph\u01b0\u01a1ng ph\u00e1p ch\u01a1i h\u1ee3p l\u00fd, hi\u1ec7u qu\u1ea3 nh\u1ea5t. V\u1edbi c\u00e1ch tr\u00fang l\u00f4 xi\u00ean \u0111\u01b0\u1ee3c \u0111\u00fac k\u1ebft r\u1ea5t th\u1ef1c ti\u1ec5n. Ch\u00fac c\u00e1c b\u1ea1n tr\u1edf th\u00e0nh ng\u01b0\u1eddi ch\u01a1i may m\u1eafn.<\/p>\n\n\n
<\/p>\r\n
\u0110\u1ed1i v\u1edbi nh\u1eefng cao th\u1ee7 ch\u01a1i l\u00f4 \u0111\u1ec1 x\u1ed5 s\u1ed1 online chuy\u00ean nghi\u1ec7p th\u00ec c\u00e1ch xem l\u00f4 xi\u00ean chu\u1ea9n x\u00e1c kh\u00f4ng c\u00f2n xa l\u1ea1 g\u00ec n\u1eefa. Nh\u01b0ng \u0111\u1ec3 hi\u1ec3u r\u00f5… Read more »<\/a><\/p>\n","protected":false},"author":1,"featured_media":17688,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[],"tags":[3190,2772,3250,3247,2773,2727,2932,3253,3249,3257,2931,2718,2927,3256,2715,3246,2840,3248,3254,3255,3252,3251],"yoast_head":"\n